C program to check leap year

C program to check leap year:

By Ahmad Irshad | C Programming Exercises and Solutions > If...Else  

Write a C program to input year from user and check whether a given year is a leap year or not using if...else. Let's see the below step by step logic to check  whether a given year is a leap year or not.

Example:

1. INPUT
2. Enter year to check leap year: 2020
3. 
   

  OUTPUT

2020 is a leap year.

Required knowledge for this exercise

Input / output | Variables | Data types | If-else | Relational operator | Logical operator | Arithmetic operator

Logic to check whether a given year is a leap year or not:

Leap year is a special year that contains an extra day (extra day is also known as leap day), that extra day is added to the end of the month, February. Therefore, February has 29 days instead of 28 days and leap year has 366 days instead of common 365 days. Leap years occur on every four years.

Now let's see the below step by step logic to check divisibility of a number.

1) Input a year from user and store it in variable year using scanf() function.

2) Check if yearis exactly divisible by 4 but not divisible by 100then, it is a leap year. OR if yearis exactly divisible by 400

then,

 that year is also a leap year.

 

Program to check leap year using if...else statement:

For Example:

1. /* C Program to check whether given year is a leap year or not. */

   
   

     #include <stdio.h>

    

     int main()

     {

       int year;

    

       /* Input a year from user */

       printf("Enter a year: ");

       scanf("%d", &year);

    

       /*

        * If any year is divisible by 4 but not divisible by 100,

        * then it is a leap year or if year is divisible by 400,

        * then it is also a leap year. see below algorithm

        */

    

       if(((year % 4 == 0) && (year % 100 !=0)) || (year % 400==0))

       {

           printf("Yes! %d is a leap year", year);

       }

       else

       {

           printf("NO! %d is not a leap year %d", year);

       }

    

       return 0;

    }

Note: As you can see in above programiforelsebody contains only single statement. Hence, you can ignore braces {} after ifandelsestatement. 

For Example:

1. if(((year % 4 == 0) && (year % 100 !=0)) || (year % 400==0)) printf("Yes! %d is a leap year", year); else printf("NO! %d is not a leap year %d", year);
   

Output:

1. Enter year to check leap year: 2020
2. Yes! 2020 is a leap year.

1. 
   
2. Enter year to check leap year: 2003
3. No! 2003 is not a leap year.

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